Two Parallel Resistors
R1 = | RTR2 |
R2 - RT |
R2 = | RTR1 |
R1 - RT |
RT = | R1R2 |
R1 + R2 |
R1: | |
R2: | |
RT: | |
How To Use:
- Fill in all but one box, hit the Solve button and the unfilled box will be computed.
- In resistor boxes, optionally use: 'k'|'M'|'G'|'m'. Example: "1k" for 1000Ω.
- Use Clear to empty a box and thus clear* the way for Solve to compute a new value.
Voltage Divider
Vtop: | ||||
R1: | ||||
R2: | ||||
R1, R2 Tolerance: | ||||
Min | Nom | Max | ||
Vout: | ||||
Vtop-Vout: | ||||
Idiv: | ||||
How To Use:
- Fill in all but one box (or in some cases two boxes can be empty — both R1 & R2, Example), hit the Solve button and the unfilled box(es) will be computed if enough variables are present.
- In resistor boxes, optionally use: 'k'|'M'|'G'|'m'. Example: "1k" for 1000Ω.
- In current boxes, optionally use: 'A'|'mA'|'uA'|'nA'. Example: 12mA for .012 amps
- Use Clear to empty a box and thus clear* the way for Solve to compute a new value.
LM317
IAdj |
||||
R1: | ||||
R2: | ||||
Vout:@ VRef 1.20V: |
IR1: |
|||
Vout:@ VRef 1.25V: |
IR1: |
|||
Vout:@ VRef 1.30V: |
IR1: |
|||
How To Use:
- Fill in all but one box, hit the Solve button and the unfilled box will be computed.
- In resistor boxes, optionally use 'k'|'M'|'G'|'m'. Example: 1k for 1000Ω.
- Use Clear to empty a box and thus clear* the way for Solve to compute a new value.
- Clicking on the IAdj radio buttons, will automatically solve if at least two values are present.
- There are three Vout results merely because 1.25V is the nominal value [i.e. the voltage we all hope it is]. The manufacturer's guarantee is a voltage between 1.20 and 1.30, thus the two extra cases [BTW: only the center value is editable -- the other two will update as needed].
-
The IR1 values go
Red when below recommended load current [5ma].
TLC5916
R1[Ω]: |
|||
ILED[ma]: |
below recommended 3ma. |
||
How To Use:
- Fill in all but one box, hit the Solve button and the unfilled box will be computed.
- In resistor boxes, optionally use: 'k'|'M'|'G'|'m'. Example: "1k" for 1000Ω.
- In current boxes, optionally use: 'A'|'mA'|'uA'|'nA'. Example: 12mA for .012 amps
- Use Clear to empty a box and thus clear* the way for Solve to compute a new value.
*Pun intended!