Solvation

Various Electronics Solver Apps

Two Parallel Resistors

Schematic of parallel resistors
R1 = RTR2

R2 - RT
R2 = RTR1

R1 - RT
RT = R1R2

R1 + R2
R1:
R2:
RT:
How To Use:
  • Fill in all but one box, hit the Solve button and the unfilled box will be computed.
  • In resistor boxes, use: 'k'|'M'|'G'|'m'. For instance: "1k" for 1000Ω.
  • Use Clear to empty a box and thus clear* the way for Solve to compute a new value.

Voltage Divider

Schematic of voltage divider
Vtop:
R1:
R2:
VOUT:
R1 · R2 Tolerance:
MinNomMax
Idiv:
How To Use:
  • Fill in all but one box (or in some cases two boxes can be empty — both R1 & R2, for instance), hit the Solve button and the unfilled box(es) will be computed.
  • In resistor boxes, use: 'k'|'M'|'G'|'m'. For instance: "1k" for 1000Ω.
  • In current boxes, use: 'A'|'mA'|'uA'|'nA'. For instance: 12mA for .012 amps
  • Use Clear to empty a box and thus clear* the way for Solve to compute a new value.

LM317

LM317 Pin-outs
LM317 Hook Up Diagram
LM317 Pin-outs for TO-92 & SO-8

IAdj


R1:

R2:

Vout:

@ VRef 1.20V:

IR1:

 

Vout:

@ VRef 1.25V:

IR1:

Vout:

@ VRef 1.30V:

IR1:

 
  
How To Use:
  • Fill in all but one box, hit the Solve button and the previously unfilled box will be populated with a computed result.
  • In resistor boxes, use 'k'|'M'|'G'|'m'. For instance: 1k for 1000Ω.
  • Use Clear to empty a box and thus clear* the way for Solve to compute a new value.
  • Clicking on the IAdj radio buttons, will automatically solve if at least two values are present.
  • There are three Vout results merely because 1.25V is the nominal value [i.e. the voltage we all hope it is]. The manufacturer's guarantee is a voltage between 1.20 and 1.30, thus the two extra cases [BTW: only the center value is editable -- the other two will update as needed].
  • The IR1 values go Red when below recommended load current [5ma].

TLC5916

Schematic of TLC5916

R1[Ω]:

ILED[ma]:

Red text when current
below recommended 3ma.
How To Use:
  • Fill in all but one box, hit the Solve button and the unfilled box will be computed.
  • In resistor boxes, use: 'k'|'M'|'G'|'m'. For instance: "1k" for 1000Ω.
  • In current boxes, use: 'A'|'mA'|'uA'|'nA'. For instance: 12mA for .012 amps
  • Use Clear to empty a box and thus clear* the way for Solve to compute a new value.

*Pun intended!